Question 832015
The first you need to do, is find the slope of the given line.  Solve the equation for y.
{{{4x+3y=0}}}
{{{3y=-4x}}}
{{{y=(-4/3)x}}}

the slope for this line is {{{-4/3}}}
Now we need to find a slope that is perpendicular.  Take the recriprocal and multiply it by -1.
{{{-4/3}}}'s reciprocal is {{{-3/4}}} and multiply it by -1 to get a slope of {{{3/4}}}.


Now we have {{{y=(3/4)x+b}}} as the beginning of the perpendicular line.  We still need to find b.
They give you the point (4,2), plug in the x and y values into the equation and solve for b.

{{{2=(3/4)(4/1) + b}}}
{{{2 = 3 + b}}}
{{{-1=b}}}


now the final equation is {{{y=(3/4)x-1}}}

If you would like more help, email me at ericahigley@yahoo.com.