Question 831882
QUestion 1: 
IN question one you need to change the equation into standard form in order to find the gradient
{{{16x + 4y = 2}}}
{{{4y = -16x + 2}}}
{{{y = -4x + 1/2}}}
So the gradient is -4 
:D 

Question 2: 
{{{b = 3 - a/2}}}
{{{b + a/2 = 3}}}
{{{a/2 = -b + 3}}}
{{{a = -2b + 6}}}
TA-DAH
:D