Question 70191
Find the equation of the line which is parallel to 3x – 2y = 6 and passes through the point (1,2).
:
Arrange the equation into the "y=" form, called the y intercept form, y = mx + b
3x - 2y = 6
-2y = 6 - 3x
We want y to be positive, mult equation by -1
2y = 3x - 6
:
Divide equation by 2
y = (3/2)x - 6/2
y = 1.5x - 3
:
The slope (m) = +1.5, we know that parallel lines have the same slope so using:
point/slope equation and the given points of x1 = 1, y1 = 2, m = 1.5
:
y - y1 = m(x - x1
y - 2 = 1.5(x - 1)
y - 2 = 1.5x - 1.5
y = 1.5x - 1.5 + 2
y = 1.5x + .5 is parallel and passes thru 1,2