Question 831528
Put the equation in slope-intercept form, {{{y=mx+b}}}
{{{m}}}} is the slope or gradient.
{{{16x+4y=2}}}
{{{4y=-16x+2}}}
{{{y=-4x+1/2}}}
{{{m=-4}}}
.
.
.
{{{b=3-a/2}}} or {{{b=(3-a)/2}}}
{{{a/2=3-b}}} or {{{2b=3-a}}}
{{{a=2(3-b)}}} or {{{a=3-2b}}}