Question 830416
{{{(4-6i)/2=2-3i}}}
{{{(2-3i)/(1+5i)=((2-3i)/(1+5i))((1-5i)/(1-5i))}}}
{{{(2-3i)/(1+5i)=((2-3i)(1-5i))/((1+5i)(1-5i))}}}
{{{(2-3i)/(1+5i)=(2-10i-3i+15i^2)/(1-5i+5i-25i^2)}}}
{{{(2-3i)/(1+5i)=(2-13i-15)/(1+25)}}}
{{{(2-3i)/(1+5i)=(-13-13i)/(26)}}}
{{{(2-3i)/(1+5i)=((-1)(1+i))/(2)}}}