Question 831323
Let {{{ d }}} km = the one-way distance he travels
Let {{{ s }}} km/hr = his speed on the outbound trip
{{{ s + 37.5 }}} km/hr = his speed on the return trip
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Equation for outbound trip:
(1) {{{ d = s*4 }}}
Equation for return trip:
(2) {{{ d = ( s+37.5 )*1.6 }}}
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{{{ 4s = 1.6s + 60 }}}
{{{ 2.4s = 60 }}}
{{{ s = 25 }}}
The average speed for the outbound trip is 25 km/hr
check:
(1) {{{ d = 25*4 }}}
(1) {{{ d = 100 }}}
and
(2) {{{ d = ( s+37.5 )*1.6 }}}
(2) {{{ d = ( 25 + 37.5 )*1.6 }}}
(2) {{{ d = 62.5*1.6 }}}
(2) {{{ d = 100 }}}
OK