Question 831061
How many quarts of pure alcohol must be added to 10 quarts of 10% alcohol solution to obtain a mixture which is 25% alcohol?
.
Let x = amount (quarts) of pure alcohol added
then
x + .10(10) = .25(10+x)
x + 1 = 2.5 + .25x
x = 1.5 + .25x
.75x = 1.5
x = 1.5/.75
x = 2 quarts