Question 831016
If the slope of a line is {{{ m }}}, then
the slope of any line perpendicular to it
will be {{{ -1/m }}}
-------------------
The slope of {{{ y = 2x + 1 }}} is {{{2}}}
{{{ m = 2 }}}
{{{ -1/m = -1/2 }}}
-------------------
If the general form of a straight line is
{{{ y = m*x + b }}}, then so far I have
{{{ y = (-1/2)*x + b }}}
----------------------
Now I can plug the given point (-2,3)
into this equation
{{{ 3 = (-1/2)*(-2) + b }}}
{{{ 3 = 1 + b }}}
{{{ b = 2 }}}
So, the equation is:
{{{ y = (-1/2)*x + 2 }}}
--------------------
Here is the plot of the 2 lines:
{{{ graph( 400, 400, -10, 10, -10, 10, 2x + 1, (-1/2)*x + 2 ) }}}