Question 830956
1.  The dimensions of the rectangle are x and 3x + 2
2.  Since the area is 20, we have x(3x + 2) = 20
3.  This becomes (after rearranging) 3x^2 + 2x - 20 = 0
4.  Applying the quadratic solution (ignoring negative possibilities), x = (-2 + Square_Root(4 + 240))/6 = 2.27
5.  That was the width.  The length is 2 + 3 times 2.27 = 2 + 6.81 = 8.81
6.  Check:  2.27 times 8.81 = 19.999, which proves that the answers are correct