Question 70248
<pre>	–5x + 2y = 10
	  x – 3y = 11 <pre>
Multiply the bottom equation by 5, this gives you 5x so it cancels with -5x

<pre>	–5x + 2y = 10
	 5(x – 3y = 11) <pre>
it then becomes

<pre>	–5x + 2y = 10
	 5x –15y = 55 <pre>
Now individually add the terms 5x and -5x to get 0x. Then add 2y and -15y to get -13y, and finally 10 and 55 to get 65
<pre>	0x - 13y = 65 <pre>
Now you can solve for y
<pre>  {{{ cross(-13/-13)y = 65/-13}}} <pre>Divide both sides by -13
So y=-5. Now solve for x by plugging in y.
{{{-5x+2(-5)=10}}}
{{{-5x+cross(-10+10)=10+10}}}Add 10 to both sides
{{{-5x=20}}}Simplify
{{{cross(-5/-5)x=(20/-5)}}}Divide both sides by -5
{{{x=-4}}}
So x=-4 and y=-5