Question 830762
<pre>
Let's start with the left side and see
if we can get it in the form of the
right side:

{{{ -(3)/(2*sqrt(x^5))}}}

Let's rationalize the denominator. We can't take 
the square root of an odd power of x without 
leaving a square root, as we could if it
were an even power of x. So let's get an even
power of x under the square root by multiplying by 
{{{sqrt(x)/sqrt(x)}}}. Then we will have an
even power of x under the square root and we'll be
able to take the square root just by dividing the
exponent by 2:

{{{(-3/(2*sqrt(x^5)))*(sqrt(x)/sqrt(x))}}}

{{{-3sqrt(x)/(2sqrt(x^5)sqrt(x))}}}

{{{-3sqrt(x)/(2sqrt(x^6))}}} 

{{{-3sqrt(x)/(2x^3)}}}

Edwin</pre>