Question 830749
The following probability distribution represents the probability of a randomly selected person exercising for x number of days per week. 
Calculate the probability a person does not exercise at all.
P(number = 0) = 0.1
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Number of days
Probability

0
10%

1
13%

2
27%

3
13%

4
12%

5
11%

6
7%

7
7%


What is the probability that a randomly selected individual exercised at least three times?
P(3 <= x <=7) = 1-P(0<= x <=2) 
= 1-[0.1 + 0.13 + 0.27] 
= 1-0.41 
= 0.59
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Cheers,
Stan H.
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