Question 830500
Q:
If the 10th term of a geometric sequence is 243 times larger than the 5th term, what is the common ratio of the sequence?
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A:
nth term: {{{a[n] = (a[1])(r^(n-1))}}}
5th term: {{{a[5] = (a[1])(r^4)}}}
10th term: {{{a[10] = (a[1])(r^9)}}}
{{{a[10]/a[5]}}} = {{{(a[1])(r^9)/(a[1])(r^4) = r^5 = 243}}}
Therefore, the common ratio is r = {{{highlight(3)}}}.