Question 830385
The vertex occurs for the x value between the roots, exactly in the middle.


The x intercepts are considered to be the roots.
(2x-3)(2x+1)=0
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2x-3=0, then {{{x=3/2}}} is one root
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2x+1=0, then {{{x=-1/2}}} is a root.
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The x value at the exact middle of these is {{{x=((3/2)+(-1/2))/2=1/2}}}
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What is the y coordinate where {{{x=1/2}}}?
Now you have your vertex, (x,y).
(Use the given equation for {{{x=1/2}}} to find the corresponding y value).



{{{graph(300,300,-2,2,-5,1,(2x-3)(2x+1))}}}