Question 830365
The focus is on the concentration of the clay.


using "units" for "yard^3",
the mixture is 6 units clay plus 4 units soil;
6+4*r=theClay units, where r is a fraction in DECIMAL form.  That is the mixture according to the purchased used quantities of clay and soil.


The first part of the description gives 10*0.84 units of clay, for the resulting mixture.  


UnitsOfClayKnown=UnitsOfClayMixed
{{{highlight(10*0.84=6+4*r)}}}
If this makes sense, then GOOD.


{{{4r=10(0.84)-6}}}
{{{r=(10(0.84)-6)/4}}}
{{{r=(8.4-6)/4}}}
{{{r=2.4/4=0.6}}}
-
The soil purchased contained 60% clay.