Question 830239
You can make use of the formula which
says: the sum of the numbers {{{1}}} through {{{n}}}
equals {{{ ( n*(n+1)) / 2 }}}
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You can test this formula:
{{{ 1 + 2 + 3 + 4 + 5 + 6 = 21 }}}
{{{ ( 6*7 ) / 2 = 21 }}}
OK
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First find the sum from {{{1}}} to {{{ 203 }}}
{{{ ( 203*204 ) / 2 = 41412/2 }}}
{{{ 41412/2= 20706 }}}
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Now find the sum from {{{1}}} to {{{57}}}
{{{ ( 57*58)/2 = 3306/2 }}}
{{{ 3306/2 = 1653 }}}
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58 + 59 + 60 + 61 + . . . 203 = {{{ 20706 - 1653 }}}
{{{ 20706 - 1653 = 19053 }}} answer