Question 830233
The first step is to put this in slope-intercept form; {{{y=mx+b}}}
{{{4y-3x=0}}}
{{{4y=3x}}}
{{{y=(3/4)x}}}


The slope for this line is {{{3/4}}}.


A line that is perpendicular would be the reciprocal times -1.


{{{3/4}}}'s reciprocal is {{{4/3}}} and times that by -1, and you get the slope of {{{-4/3}}}.


So the new line line looks like {{{y=(-4/3)x+b}}}.  We still need to find b so plug the point (-1,3) in for the x and y values.


{{{3=(-4/3)(-1)+b}}}
{{{3=(4/3) + b}}}
{{{3-(4/3)=b}}}
{{{1(2/3)=b}}}


{{{y=(-4/3)x + 1(2/3)}}}
------------------------------------------------------------------------------
Email me at ericahigley@yahoo.com if you would like more free step by step help from me.