Question 70112
THE LARGEST AREAS OF A TRIANGLE IS A SQUARE THUS TO FORM 2 SQUARES.
ONE SQUARE NEEDS TO HAVE A PERIMETER OF 56.999999999 INCHES THUS THE AREA IS (56.999999999/2)^2
(28.499999999)^2
812.2499 SQUARE INCHES BY THE AREA OF THE .000000001 PIECE OF WIRE.
OF COURSE IF YOU DON'T CUT THE WIRE YOU CAN GET 
(57/2)^2=812.25 IN^2
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CUTTING THE WIRE IN HALF IS THE WORST SOLUTION THUS
57/2=28.5 FOR BOTH PIECES OF WIRE.
EACH WIRE WILL ENCLOSE AN AREA OF
(28.5/2)^2 
203.0625 IN^2 FOR ONE PIECE AND 203.0625 FOR THE OTHER PIECE WHICH TOTALS ONLY
203.0625*2=406.125 IN ^2