Question 830149
{{{x = (3/4 - 4t)^2}}}, seems to be what you want, exactly as you stated.


The goal is solve for t.
{{{(3/2-4t)^2=x}}}
{{{3/2-4t=0+- sqrt(x)}}} ------ the zero is only to allow the rendering to work and is not strictly needed
{{{3-8t=0+- 2*sqrt(x)}}}
{{{-8t=-3+- 2*sqrt(x)}}}
{{{highlight(t=3/8+- (1/4)sqrt(x))}}}