Question 829898
{{{log((x))+log((4+x))=log((5))}}}
{{{log((x(4+x)))=log((5))}}}
{{{x(4+x)=5}}}
{{{x^2+4x-5=0}}}
{{{(x+5)(x-1)=0}}}
Two possible solutions:
{{{x+5=0}}}
{{{x=-5}}}
However checking in the original equation, {{{log((-5)))}}} does not exist so this is not a solution.
{{{x-1=0}}}
{{{x=1}}}
{{{log((1))+log((5))=log((5))}}}
True, this is a solution.
{{{highlight(x=1)}}}