Question 829792
Put each inequality into slope-intercept form.  Graph the line of each, but because both statements are INEQUALITIES,  the strict inequality needs a dotted line, and the inclusive inequality needs a solid line.  


Shade each half-plane for the two inequalities; the intersection of these shadings will be the solutions for the system of inequalities.  


This statement already is set for graphing:  {{{y<2x+4}}}


The other statement is worth transforming:  {{{-3x-2y>=6}}}
{{{-2y>=3x+6}}}
{{{y<=-(3/2)x-3}}}----- Easier to graph it this way.


Shade the region below the line of {{{y<2x+4}}} using strokes in one direction.
Shade the region below the line of {{{y<=-(3/2)x-3}}} using strokes in a different direction than for the other line.  This will make the intersection of shadings very easy to see.