Question 829800
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x = Jenny
y = Jason
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x + 1 = 3(y + 1) - 2
x + 1 + y + 1 = 18
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put the system of linear equations into standard form:
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x + 1 = 3y + 1
x + y + 2 = 18
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x - 3y = 0
x + y = 16
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their ages today:
x = Jenny = 12
y = Jason = 4
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their ages on their next birthday:
x = Jenny = 13
y = Jason = 5
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Solve and graph linear equations:
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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