Question 829708

{{{(1/3)(y+2)=3y-5(y-2)}}}.......both sides multiply by {{{3}}} to get a rid of fraction

{{{3(1/3)(y+2)=3*3y-3*5(y-2)}}}

{{{cross(3)(1/cross(3))(y+2)=9y-15(y-2)}}}

{{{y+2=9y-15(y-2)}}}

{{{y+2=9y-15y+30}}} ........move unknown variable to the left and known t the right

{{{y-9y+15y=30-2}}}

{{{7y=28}}}

{{{y=28/7}}}

{{{y=4}}}