Question 829453
How many gallons of a 14% salt solution must be mixed with a 38% salt solution to make 40 gallons of 20% salt solution? 
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Equation:
salt + salt = salt
0.14x + 0.38(40-x) = 0.20*40
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14x + 38(40) - 38x = 20*40
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-24x = -18*40
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x = (3/4)40
x = 30 gallons (amt. of 14% solution needed)
40-x = 10 gallons (amt. of 38% solution needed)
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Cheers,
Stan H.
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