Question 829446
Use x,y notation.
{{{y=(3-4x)^2}}}
Now interchange x and y and solve for y.
{{{x=(3-y)^2}}}
Take the square root of both sides:
{{{sqrt(x)=3-y}}} and {{{-sqrt(x)=3-y}}}
{{{y=3 + sqrt(x)}}} and {{{y=3-sqrt(x)}}}
This "new" y is the inverse of the original function.
{{{ graph( 300, 200, -2, 10, -10, 10, (3-4x)^2, 3-sqrt(x), 3+sqrt(x)) }}} 
The inverse is not a function since it does not provide one y value for each x value, it provides 2.