Question 829363
what is the next number in this series 4, 7, 16, 43, 124
<pre>
Rule: {{{t[n] = t[n - 1] + 3^(n - 1)}}}, with {{{t[1] = 4}}}
Thus, the 6th term is: {{{t[6] = t[6 - 1] + 3^(6 - 1)}}}, or {{{t[6] = t[5] + 3^(5)}}}.
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