Question 829334

Bart can peel a batch of 3000 lbs of apples in 12 hours with an old machine, while Mona can do the same job in 8 hrs using the new machine. If Bart starts peeling at 8am and Mona joins him at 9am then at what time will they finish the batch working together. So far I have 1/t1+1/t2=1/t3 so that is 1/12+1/8=1/x
2x+3x=24
6x=24
x=4 but I am clueless as to what I am supposed to do with the extra hour Bart has?<pre>You need to realize that Bart can do the job in 12 hours, or {{{1/12}}}, of job in 1 hour
Therefore, in 1 hour (8:00 AM - 9:00 AM), he has completed {{{1/12}}} of the job, which leaves {{{11/12}}} to be completed
by he and Mona.

Working together to complete the {{{11/12}}} remaining work, you should get 4.4 hours, or {{{4&2/5}}} hours, or 4 hours, 24 minutes,
after both start (9:00 AM), which makes the end-time: {{{highlight_green(13:24_HOURS)}}}, or {{{highlight_green(1:24_PM)}}}
You can do the check!! 

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