Question 829302
{{{2a-4b=6}}}
{{{-a+2b=-3}}}
solve one of the equations for a.
{{{2a-4b=6}}}
{{{2a-4b+4b=6+4b}}}
{{{2a=4b+6}}}
{{{2a/2=(4b+6)/2}}}
{{{a=2b+3}}}
You can use the substitution method by replacing any a with 2b+3 since a is equal to 2b+3.
{{{-a+2b=-3}}}
{{{-(2b+3)+2b=-3}}}
{{{-2b-3+2b=-3}}}
{{{-3=-3}}}
whenever you are left without the variable, and the statement is true, ie -3 is equal to -3, then it means infinite solutions. if it were untrue, ie 5 is equal to 2, then it would be no solution.  Since -3=-3, b=any number.  And since b is any number, a would also be any number.
answer: a=any number, b=any number
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