Question 828946
f(f(x) = m(mx + b) + b = m^2(x) + bm + b
.
And, they give you:
f(f(x)= 9x + 4
.
Your two equations are:
m^2 = 9 (equation 1)
and
bm+b = 4 (equation 2)
.
Solving equation 1:
m^2 = 9
m = 3
.
Substitute above into equation 2:
bm+b = 4
b(3)+b = 4
4b = 4
b = 1
.
solution then:
m = 3 and b = 1
so
f(x) = 3x+1