Question 68799
{{{(2x)/(x^2 - 13x + 42)-(7)/(x - 6)}}}First rewrite denominator of left fraction
{{{(2x)/((x-6)(x-7))-(7)/(x - 6)}}}Factor denominator
{{{(2x)/((x-6)(x-7))-((x-7)/(x-7))((7)/(x - 6))}}} Multiply right fraction by {{{(x-7)/(x-7)}}} to give both fractions a common denominator
{{{(2x)/((x-6)(x-7))-(7x-49)/((x - 6)(x-7))}}}Now you can subract
{{{(2x-7x+49)/((x-6)(x-7))}}}Simplify
{{{(-5x+49)/((x-6)(x-7))}}}To verify, pick any value for x (say 1) and plug it into both expressions and they'll be equal.