Question 70085
(X+5)^2=3
X^2+10X+25-3=0
X^2+10X+22=0
USING THE QUADRATIC EQUATION WE GET 
X=(-B+-SQRT[B^2-4AC])/2A
X=(-10+-SQRT[10^2-4*1*22])/2*1
X=(-10+-SQRT[100-88])/2
X=(-10+-SQRT12)/2
X=(-10+-3.464)/2
X=(-10+3.464)/2
X=-6.536/2
X=-3.268 ANSWER
X=(-10-3.464)/2
X=-13.464/2
X=-6.732 ANSWER