<PRE><B>Question 828520</B>
line k is x+3y=6, now put k in standard form ( y = mx +b )
y = -x/3 +2
i)  three points on line k, (0,2), (3, 1), (-3, 3)  note you pick x value, then solve for y
ii) graph of y = -x/3 +2
{{{ graph( 300, 200, -10, 10, -10, 10, -x/3 +2) }}}
iii) slope (m) of k is -1/3
iv) is (-54, 20) on line k?
20 = -(-54)/3 +2
20 = 18 +2
20 = 20
yes, point (-54, 20) lies on line k
 
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