Question 828478
n is an integer, greater than zero.
Three even integers may be 2n, 2n+2, 2n+4.


{{{(2n+4)^2=(2n)^2+(2n+2)^2+12}}}
{{{4n^2+16n+16=4n^2+4n^2+8n+4+12}}}
{{{16n+16=4n^2+8n+16}}}
{{{16n=4n^2+8n}}}
{{{4n=n^2+2n}}}
{{{2n=n^2}}}
{{{n^2-2n=0}}}
{{{n(n-2)=0}}}
The meaningful solution for n is {{{highlight_green(n=2)}}}
The three even consecutive integers are 4, 6, and 8.