Question 828461
Hi,
Could you please help me solve the below problem. Much appreciate your help. Thank you very much for your time and help.
regards
Simsasha

Four parcels have a total weight of 22 Kgs. Parcel 1 is 4 times the weight of parcel 3. Parcel 4 is half the weight of parcel 2. If parcel 1 weighs 8 Kgs., how much does parcel 4 weigh.

I tried to work this out as follows and got stuck.
Parcel 1 = 8
parcel 2 = X
parcel 3 = 2
Parcel 4 = x/2

8+X+2+X/2 = 22
10+X+X/2 + 22
X+X/2 = 22-10
X+X/2=12
<pre><b>
Let weight of parcel 4, be F
Then weight of parcel 2 is: 2F
Weight of parcel 1:         8 kg
Weight of parcel 3:         {{{1/4}}} of parcel 1, or {{{1/4}}} of 8, or 2 kg

Altogether they weigh 22 kg, so we can say that:
F + 2F + 8 + 2 = 22
3F + 10 = 22
3F = 22 - 10 
F, or weight of parcel 4 is: {{{12/3}}}, or {{{highlight_green(4)}}} kg
You can do the check!! 

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