Question 828452
tickets at a concert cost $8 for section A and $4.25 for section B. In total 4500 tickets were sold worth $30000. How many of each type of ticket were sold?


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Let x = # of section A tickets sold
Let y = # of section B tickets sold


4500 tickets were sold, so x+y = 4500. Solve for y to get y = 4500-x


"tickets at a concert cost $8 for section A and $4.25 for section B. In total 4500 tickets were sold worth $30000" all translates to the equation below


8x + 4.25y = 30000


8x + 4.25(4500-x) = 30000 ... plug in y = 4500 - x


8x + 4.25(4500) + 4.25(-x) = 30000


8x + 19125 - 4.25x = 30000


3.75x + 19125 = 30000


3.75x = 30000 - 19125


3.75x = 10875


x = 10875/3.75


x = 2900


y = 4500 - x


y = 4500 - 2900


y = 1600


Since x = 2900 and y = 1600 this means that 


<font color="red">2900</font> section A tickets were sold
<font color="red">1600</font> section B tickets were sold