Question 828372
{{{3^2 + (-2)^3+ (4^2-5)}}} has 3 terms:
{{{3^2}}} , {{{(-2)^3}}} , and {{{(4^2-5)}}} ,
separated by signs indicating addition.
According a very widely accepted old convention, addition and subtraction are the last operations we do when more than one operation is indicated (except as directed by parentheses).
Evaluating terms {{{3^2}}} , and {{{(-2)^3}}} is straight forward.
Term {{{(4^2-5)}}} is wrapped in parentheses for no good reason.
In this particular case, the expressions with and without those parentheses are equivalent.
However, I will pretend I don't know that and I will calculate what's inside the parentheses first.
{{{4^2-5}}} is calculated by evaluating {{{4^2}}} first and subtracting {{{5}}} after that.
 
All in all,
{{{3^2 + (-2)^3+ (4^2-5)=9+4+(16-5)=9+4+9=highlight(22)}}}