Question 828291
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the problem tries to confuse you, but it's basically describing a right triangle, and asking you to find the hypotenuse, given the two legs.
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find the position of both ships at 5 pm so we know the length of legs a and b:
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speed and distance formulas:
s = d/t
d = t*s
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ship1 at 5 pm:
time = 5 - 1 = 4 hours
speed x m/hr
position = 4x west of harbor
a = 4x
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ship2 at 5 pm:
time = 5 - 3 = 2 hours
speed y m/hr
position = (100-2y) south of harbor
b = (100-2y)
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the positions of the ships are perpendicular relative to the harbor, so the ship positions form the legs of the right triangle, and the harbor is the 90 degree vertex.
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hyp = sqrt( aa + bb )
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answer:
hyp = sqrt( 16xx + (100-2y)(100-2y) )
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