Question 828121
First integer : {{{N}}}
Next two consecutive integers : {{{N+1}}},{{{N+2}}}
The sum of first and twice the second : {{{N + 2*(N+1)}}}
is means "equals"
80 minus three times the third : {{{80-3*(N+2)}}}
So then,
{{{N+ 2*(N+1)=80-3*(N+2)}}}
{{{N+2N+2=80-3N-6}}}
I leave you that to solve for {{{N}}}.
Re-post if you still need help.