Question 827846
What you describe can also be written as
f(g(h(x)))
Since {{{h(x) = x^2}}} we can substitute in:
{{{f(g(x^2))}}}
Since g(x) = sin(x), then {{{g(x^2) = sin(x^2)}}}. Substituting this in we have:
{{{f(sin(x^2))}}}
Since f(x) = 6x-5:
{{{f(sin(x^2)) = 6(sin(x^2))-5 = 6sin(x^2)-5}}}<br>
So {{{f(g(h(x))) = 6sin(x^2)-5}}}