Question 828010
The diagonal of a rectangle is 15m long and one side is 2m longer than the other. 
.
Let w = width
then
w+2 = length
.
applying Pythagorean's theorem:
w^2 + (w+2)^2 = 15
w^2 + (w+2)(w+2) = 15
w^2 + w^2+4w+4 = 15
2w^2+4w+4 = 15
2w^2+4w-11 = 0
applying the quadratic formula we get:
w = 1.55 m (width)
.
Length:
w+2 = 1.55+2 = 3.55 m (length)
.
Dimensions are:
1.55m by 3.55 m
.
Details of quadratic formula:
*[invoke quadratic "w", 2, 4, -11 ]