Question 827911

{{{ (x+5)/5-(2x-12)/7=1 }}} ............both sides multiply by {{{35}}} which is divisible with both {{{5}}} and {{{7}}}


{{{35(x+5)/5-35(2x-12)/7=1*35}}}


{{{cross(35)7(x+5)/cross(5)-cross(35)5(2x-12)/cross(7)=35}}}


{{{7(x+5)-5(2x-12)=35}}}


{{{7x+35-10x+60=35}}}.............you probably made mistake here when multiply {{{-5}}} and {{{-12}}}


{{{-3x+95=35}}}


{{{95-35=3x}}}


{{{60=3x}}}


{{{60/3=x}}}


{{{20=x}}}