Question 827892

{{{log(6,(x-2)) + log(6,3) = log(6,2)}}}


{{{log(6,(x-2)*3) = log(6,2)}}}....since log of same base is equal, then


{{{(x-2)*3 = 2}}} ....is equal too; so, all we need is to solve for {{{x}}}


{{{x-2 = 2/3}}}

{{{x= 2/3+2}}}

{{{x= 2/3+6/3}}}

{{{x= 8/3}}}