Question 69956
   
  
   {{{x^2-5x-14 = 0}}}
 = {{{x^2+2x-7x-14 = 0}}} = {{{x(x+2)-7(x+2)=0}}} = {{{(x+2)(x-7)=0}}}
So, either (x+2) or (x-7) = 0.  If (x+2) = 0, then x = -2.  If (x-7) = 0, 
then x = 7.  
x = {-2, 7}.  Answer.
 
gsm