Question 827710
{{{log((x-4)) = -2 + log((x+3))}}}
log(1/100) = -2 since {{{(10^(-2))}}}={{{(1/(10^2))}}}={{{(1/100)}}}
so {{{log((x-4)) = -2 + log((x+3))}}} = {{{log((x-4)) = log(1/100) + log((x+3))}}}
This solution assumes that log means log base 10.
{{{log((x-4)) = log(((1/100)*(x+3)))}}}
so x-4 = (1/100)*(x+3)
multiply each side by 100
100(x-4) = x+3
100x - 400 = x + 3
add 400 to each side
100x = x + 403
subtract x from each side
99x = 403
 x = 403/99
Let's see if it works
log((x-4)) = -2 + log((x+3))
add 2 - log((x+3)) to each side
log((x-4)) - log((x+3)) = -2 
rewriting the the left hand side and plugging into excel we can
verify that
log10(403/99 - 4) - log10( 403/99 + 3) = -2