Question 827653
49c+55a=56290
a and c both must be positive integers (whole numbers)
if a=0 then c = 1148.8
if c=0 then a = 1023.5
so a < 1023.5 and c < 1148.8
a = 49n+39 and c = 1105-55n
a = 88,    c = 1050,  n=1
a = 137,   c = 995,   n = 2
a = 186,   c = 940,   n = 3
a = 235,   c = 885,   n = 4
a = 284,   c = 830,   n = 5
we could pin it down to one answer if we knew the total number of tickets sold.