Question 827589
x=base
y=height
{{{y=x+2}}}
and
{{{(1/2)xy=40}}}
'
{{{(1/2)x(x+2)=40}}}
{{{x^2+2x=80}}}
{{{x^2+2x-80=0}}}
{{{(x-8)(x+10)=0}}}
{{{x=8}}}, the solution that makes sense.


ANSWER:   x=8 and y=10