Question 827432
1e) Find the probability of scoring a total of 16. 
Note (The whole question is about a uniform distribution of fair dice. 
Question 1d) asked what the different ways to score 16 were, and my answer was 
"4+6+6"; 6+4+6; 6+6+4
"5+5+6"; 5+6+5; 6+5+5
So, P(sum = 16) = 6/216
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Also question 1c) asked what the probability of all three numbers being 6 and the answer was (1/216)).... Correct
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Cheers,
Stan H.