Question 827450
three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now?
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1st: 5x-5
2nd: 5x
3rd: 5x+5
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Equation:
5x-7 + 5x-2 + 5x+3 = 69
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15x - 6 = 69
15x = 75
x = 5
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1st: 5x-5 = 25-5 = 20 yrs
2nd: 25 yrs
3rd: 30 yrs
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Cheers,
Stan H.
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