Question 827347
x^2(x-16)(x-4) = 0
we want values of x so the left hand side = 0
So we need to solve
x^2 = 0
x-16 = 0
and
x-4 = 0

Take x^2 = 0
 x = 0 is the solution here.
Take x-16 = 0
 subtract 16 from each side
    x = 16
Take x-4 = 0
 subtract 4 from each side
    x = 4

so the possible values for x are 0, 16, and 4