Question 827122
log base 16 of x + log base 4 of x + log base 2 of x = 7
solve for x
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{{{log(2,(x))/log(2,(16))+log(2,(x))/log(2,(4))+log(2(x))=7}}}
{{{log(2,(x))/3+log(2,(x))/2+log(2(x))=7}}}
LCD:6
{{{2log(2,(x))+3log(2,(x))+6log(2(x))=42}}}
{{{log(2,(x^11))=42}}}
2^42=x^11
raise both sides to 1/11 power
x=2^(42/11)
x≈14.10546..